7g^2-39g=0

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Solution for 7g^2-39g=0 equation:



7g^2-39g=0
a = 7; b = -39; c = 0;
Δ = b2-4ac
Δ = -392-4·7·0
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-39}{2*7}=\frac{0}{14} =0 $
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+39}{2*7}=\frac{78}{14} =5+4/7 $

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